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Q.

In which of the following ionization processes the bond energy increases and the magnetic behaviour changes from paramagnetic to diamagnetic.

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a

O2→O2+

b

C2→C2+

c

NO→NO+

d

N2→N2+

answer is C.

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Detailed Solution

Molecular orbital configuration ofO2⇒σ1s2σ*1s2σ2s2σ*2s2σ2pz2π2px2π2py2π*2px1π*2py1 ⇒ Paramagnetic   Bondorder =10-62=2 O2+⇒σ1s2σ*1s2σ2s2σ*2s2σ2pz2π2px2π2py2π*2px1 ⇒ Paramagnetic   Bondorder =10-52=2.5 C2⇒σ1 s2σ*1 s2σ2 s2σ*2 s2π2px2π2py2 ⇒ Diamagnetic   Bondorder =8-42=2 C2+⇒σ1 s2σ*1 s2σ2 s2σ*2 s2π2px2π2py1 ⇒ Paramagnetic   Bondorder =7-42=1.5 NO⇒σ1 s2σ*1 s2σ2 s2σ*2 s2σ2pz2π2px2π2py2π*2px1 ⇒ Paramagnetic   Bondorder =10-52=2.5 NO+⇒σ1s2σ*1s2σ2s2σ*2s2σ2pz2π2px2π2py2 ⇒ Diamagnetic.  NO+⇒σ1 s2σ*1 s2σ2 s2σ*2 s2σ2pz2π2px2π2py2 ⇒ Diamagnetic.   Bondorder =10-42=3 N2⇒σ1s2σ*1s2σ2s2σ*2s2π2px2π2py2σ2pz2 ⇒ Paramagnetic   Bondorder =9-42=2.5 ⇒ Paramagnetic
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