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a
ZnS (Ksp = 7 × 10–16)
b
Fe(OH)3 (Ksp = 6 × 10–38)
c
Be3(PO4)2 (Ksp = 6 × 10–39)
d
Ag3PO4 (Ksp = 1.8 × 10–18)
answer is D.
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Detailed Solution
Ag3PO4[s]⇌Ag3PO4[aq]→3Ag+3S[aq]+PO4S-3[aq]Ksp=(3S)3×S⇒ 1.8 x 10-18 = 27 x S4⇒ 20 x 10-16 = 3 x S4Solubility, S will be of the order of 10-4 which is the largest among other option.