First slide
PH scale, PH of strong acids and strong bases
Question

Which of the following is not correct ?

Easy
Solution

P^H=-log[H^+]=log[H^+]^{-1}=log\frac{1}{[H^+]}

Also, [H^+]=10^{-P^H}\Rightarrow P^H=-log{[H^+]}

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App