Which of the following is not correct for SF6?

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Hybridization in SF6 is sp3d2 where d orbitals are dz2 and dx2-y2.

All F—S—F angles are 90o.

Geometry and shape of SF6 is octahedral.

Axial bonds are longer than equatorial bonds.

answer is D.

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Detailed Solution

All positions and bond lengths in octahedral SF6 are equal. There are no separate equatorial and axial positions.

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