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a
CaCO3⟶CaO+CO2
b
O2+2H2⟶2H2O
c
Na+H2O⟶NaOH+12H2
d
MnCl3⟶MnCl2+(1/2)Cl2
answer is A.
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Detailed Solution
Oxidation states of Ca and C are +2 and +4, respectively, in both reactant and product; hence, not redox. (2) 4e−+O2⟶2O2−( Reduction )H2⟶2H⊕+2e−(Oxidation) Hence, redox,(3) Na→ Na⊕+e- (Oxidation) 2H⊕+2e-→ H2O(Reduction) Hence, redox.(4) e-+Mn3+→ Mn2+(Reduction) 2Cl⊝→ Cl2+2e-(Oxidation) Hence, redox.