Q.
Which of the following options represents the correct bond order?
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a
O2->O2>O2+
b
O2-
c
O2->O2
d
O2-O2+
answer is B.
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Detailed Solution
Electronic configuration of O2(16 electrons) =σls2,σ*ls2,σ2s2,σ*2s2,σ2pz2,π2px2≈π2py2π*2px1≈π*2py1 Bond order =12Nb-Na=12(10-6)=2 Electronic configuration of O2+(15 electrons )=σ1s2,σ*1s2,σ2s2,σ*2s2,σ2pz2,π2px2≈π2py2π*2px1≈π*2py0 Bond order =12Nb-Na=12(10-5)=2.5 Electronic configuration of O2-(17 electrons) =σ1s2,σ*1s2,σ2s2,σ*2s2,σ2pz2,π2px2≈π2py2π*2px2≈π*2py1 Bond order =12Nb-Na=12(10-7)=1.5 Thus, the order of bond order is O2-
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