Which of the following options represents the correct bond order?

Electronic configuration of O2(16 electrons) =σls2,σ*ls2,σ2s2,σ*2s2,σ2pz2,π2px2≈π2py2π*2px1≈π*2py1 Bond order =12Nb-Na=12(10-6)=2 Electronic configuration of O2+(15 electrons )=σ1s2,σ*1s2,σ2s2,σ*2s2,σ2pz2,π2px2≈π2py2π*2px1≈π*2py0 Bond order =12Nb-Na=12(10-5)=2.5 Electronic configuration of O2-(17 electrons) =σ1s2,σ*1s2,σ2s2,σ*2s2,σ2pz2,π2px2≈π2py2π*2px2≈π*2py1 Bond order =12Nb-Na=12(10-7)=1.5 Thus, the order of bond order is O2-