Which of the following options represents the correct bond order?

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

O2->O2>O2+

O2-

O2->O2

O2-O2+

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Electronic configuration of O2(16 electrons) =σls2,σ*ls2,σ2s2,σ*2s2,σ2pz2,π2px2≈π2py2π*2px1≈π*2py1 Bond order =12Nb-Na=12(10-6)=2 Electronic configuration of O2+(15 electrons )=σ1s2,σ*1s2,σ2s2,σ*2s2,σ2pz2,π2px2≈π2py2π*2px1≈π*2py0 Bond order =12Nb-Na=12(10-5)=2.5 Electronic configuration of O2-(17 electrons) =σ1s2,σ*1s2,σ2s2,σ*2s2,σ2pz2,π2px2≈π2py2π*2px2≈π*2py1 Bond order =12Nb-Na=12(10-7)=1.5 Thus, the order of bond order is O2-

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET