Which of the following orders of boiling points is correct?
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a
H2O>H2S>H2Se
b
H2O>H2S
c
H2OH2Se
d
H2O
answer is B.
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Detailed Solution
Because of hydrogen bonding, the boiling, the boiling point of H2O is greater than that of H2S. The boiling point of H2S is smaller than H2Se as the former is a lighter molecule.