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Q.

In which of the following pairs does the first gas bleaches flowers by reduction while the second gas does so by oxidation

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a

CO and Cl2

b

SO2 and Cl2

c

H2 and Br2

d

NH3 and SO2

answer is B.

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Detailed Solution

SO2 bleaches flower by reduction2H2O+SO2→H2SO4+2H2H+Coloured flower→ReductionColourless reduced flowerThis bleaching is temporary because reduced flower again oxidised by air to form coloured flower Cl2+H2O→2HCl+OO+Coloured flower→OxidationColourless Oxidised flowerThis bleaching is permanent because oxidised flower remains colourless.
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