Which of the following pairs have identical values of bond order ?
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a
N2+ and O2+
b
F2 and N2
c
O2 and B2
d
C2 and N2
answer is A.
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Detailed Solution
(a) Bond order of N2+=9-42=2.5 ; The bond order of O2+ = 1/2(10-5)=2.5(b) Bond order of F2=10-82=1 ; The bond order of Ne2=0.(c) Bond order of O2=10-62=2 ; The bond order of B2=6-42=1.(d) Bond order of C2=10-82=2 ; The bond order of N2=10-42=3.