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a
B2
b
C2
c
N2
d
F2
answer is A.
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Detailed Solution
Paramagnetic species has unpaired electron.B2=5+5=10σ1s2,σ∗1s2,σ2s2,σ∗2s2,π2px1=π2py1C2=6+6=12=σ1s2,σ∗1s2,σ2s2,σ∗2s2,π2px2=π2py2N2=7+7=14=σ1s2,∗1s2σ2s2,σ∗2s2π2px2=π2py2,σ2pz2F2=9+9=18=σ1s2,σ∗1s2,σ2s2,σ∗2s2,σ2pz2,π2px2=π2py2,π∗2px2=π∗2py2∴ B2 is paramagnetic because it has unpaired electron.