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Q.

Which of the following paramagnetic species has the highest bond order

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a

N2

b

O2+

c

O2-

d

C2-2

answer is B.

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Detailed Solution

N2 & C2-2 (14 electrons) - diamagneticO2+ (paramagnetic)- KKσ2s2σ*2s2σ2px2(π2py2=π2pz2)(π*2py1=π*2pz0) Bond order =nb-na2=10-52=2.5O2-(paramagnetic)- KKσ2s2σ*2s2σ2px2(π2py2=π2pz2)(π*2py2=π*2pz1) Bond order =nb-na2=10-72=1.5

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