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An Intiative by Sri Chaitanya
a
XeF2+HF⟶HXeF3
b
XeF6+RbF⟶XeF5RbF2
c
XeF4+PF5⟶XeF3PF6
d
3XeF4+6H2O⟶2Xe+XeO3+12HF+12O2
answer is .
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