First slide

Chemical reactions and calculations

Question

Which of the following represents a redox reaction?

Easy

A

$NaOH + HCl ⟶ NaCl + H_{2} O$
B

${BaCl}_{2} + H_{2} {SO}_{4} ⟶ {BaSO}_{4} + 2 HCl$
C

${CuSO}_{4} + 2 H_{2} O ⟶ Cu (OH)_{2} + H_{2} {SO}_{4}$
D

$Zn + 2 HCl ⟶ {ZnCl}_{2} + H_{2}$

Solution

(1) and (2) are neutralisation reactions.
(3) The oxidation state of Cu is +2 in both reactant and product, and ${SO}_{4}^{2 -}$ ion does not change. So it is none reaction.
(4) It is a redox reaction.
$\begin{array}{l} Zn ⟶ {Zn}^{2 +} + 2 e^{-} (Oxidation) \\ 2 H^{\oplus} + 2 e^{-} ⟶ H_{2} (Reduction) \end{array}$

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