Which of the following setups is correct to calculate the weight (in g) of KCIO₃ produced from the reaction of 0.150 moles of Cl₂?
$3{\mathrm{Cl}}_2+6\mathrm{KOH}⟶5\mathrm{KCl}+{\mathrm{KClO}}_3+3{\mathrm{H}}_2\mathrm{O}$

• A

  0.150 moles Cl₂ x 1 mole KClO₃/3 moles Cl₂ x 122.5 g/1 mole KCIO₃,

• B

  0.150 moles Cl₂ x 1 mole KCIO₃ /3 moles Cl₃ x l mole KCIO₃/122.5 g

• C

  0.150 moles Cl₂ x 3 moles Cl_2/1 mole KClO₃ x 122.5 g/1 mole KClO₂,

• D

  0.150 moles Cl₂ x 3 moles Cl₂/1 mole KCIO₃, x 1 mole KCIO₃./122.5 g