Which of the following solution exactly reduces 25 ml of 0.2N KMnO4 solution in acidic medium?

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25 mL of 0.2 M FeSO4 to be oxidized to Fe3+

50 mL of 0.1 M H3AsO3 to be oxidized to H3AsO4

25 mL of 0.1 M H2O2 to be oxidized to H+ and O2

25 mL of 0.1 M SnCl2 to be oxidized to Sn4+

answer is A.

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Detailed Solution

Milli equivalent of KMnO4=25×0.2=5 meq. 1.Fe2+⟶Fe3+ Milli equivalent of FeSO4=25×0.2×1=0.2×25=5 (same) 2.H3AsO3⟶H3AsO4 Milli equivalent of H3AsO3=2×50×0.1=10 (not same) 3. H2O2⟶2H++O2 Milli equivalent of H2O2=25×0.1×2=5 (same) 4.Sn2+⟶Sn4+ Milli equivalent of SnCl2=25×0.2=25×0.1=5 (same)

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