Which of the following solutions will have pH of 4.74?
100mL of 1MCH3COOHpKa=4,74 at rhe equivalence point using NaOH
50mL of 1MCH3COONa+25mL of 1MHCl
50mL of 1M of CH3COOH+25mL of 1MNaOH
Both (b) and (c)
Due to hydrolysis of CH3COONa (formed at equivalence point), solution is alkaline pH > 7, hence (a) is not true.
In (b) and (c), [CH3COOH] = [CH3COONa]
pH=pKa+logCH3COONaCH3COOH=pKa