Q.

Which of the following solutions will have pH of 4.74?

Moderate

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By Expert Faculty of Sri Chaitanya

100mL of 1MCH3COOHpKa=4,74 at rhe equivalence point using NaOH

50mL of 1MCH3COONa+25mL of 1MHCl

50mL of 1M of CH3COOH+25mL of 1MNaOH

Both (b) and (c)

answer is 4.

(Detailed Solution Below)

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Detailed Solution

Due to hydrolysis of CH3COONa (formed at equivalence point), solution is alkaline pH > 7, hence (a) is not true. In (b) and (c), [CH3COOH] = [CH3COONa]pH=pKa+log⁡CH3COONaCH3COOH=pKa

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