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 Which of the following species has its bond order greater than that of O2 and is paramagnetic with one unpaired electron in pi anti bonding molecular orbital

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By Expert Faculty of Sri Chaitanya
a
O2
b
O2+
c
O2-
d
O2-2

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detailed solution

Correct option is B

O2-2-KK'σ2s2σ2s*2σ2pz2π2px2π2py2π2px*2π2py*2O2--KK'σ2s2σ 2s*2σ2pz2π2py2π2py2π2px*2π2py*1O2 -KK'σ2s2σ2s*2σ2pz2π2px2π2py2π2px*1π2py*1O2+-KK'σ2s2σ2s*2σ2pz2π2px2π2py2π2px*1π2py*0Bond order in O2-2=10-82=1; O2-=10-72=1.5; O2=10-62=2; O2+=10-52=2.5;O — O bond length inO2-2>O2->O2>O2+


Similar Questions

The increasing order of energies of various molecular orbitals are

 I. σ1s<σ*1s<σ2s<σ*2s<σ2pz<π2px=π2py<π*2px=π*2py<σ*2pz

 II. σ1s<σ*1s<σ2s<σ*2s<π2px=π2py<σ2pz<π*2px=π*2py<σ*2pz

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