First slide
Modern approach of classification of elements
Question

Which of the following statement is/are correct?

Moderate
Solution

Statement (a) is wrong.

Cu(Z=29),3d10,4s1Cu( cuprous )=3d104s0Cu2+( cupric )=3d94s0

(one unpaired electron and hence is coloured)

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App