Q.
Which of the following statement is incorrect for dry cell ?
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a
Reaction at cathode MnO2+NH4++e−⟶MnO(OH)+NH3
b
Manganese is reduced from +5 to +4 state
c
Cell potential is 1.5 V
d
Ammonia form complex with Zn2+ to give ZnNH342+
answer is B.
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Detailed Solution
Anode Zn(s)⟶Zn2+(aq)+2e− Cathode MnO2+NH4++e−⟶MnO(OH)+NH3At cathode manganese is reduced from +4 oxidation state to +3 oxidation state. Ammonia produced in reaction from complex with Zn2+ to give ZnNH242+. The cell has potential of 1.5 V.
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