Q.

Which of the following statement is incorrect for dry cell ?

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Reaction at cathode MnO2+NH4++e−⟶MnO(OH)+NH3

Manganese is reduced from +5 to +4 state

Cell potential is 1.5 V

Ammonia form complex with Zn2+ to give ZnNH342+

answer is B.

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Detailed Solution

Anode Zn(s)⟶Zn2+(aq)+2e− Cathode MnO2+NH4++e−⟶MnO(OH)+NH3At cathode manganese is reduced from +4 oxidation state to +3 oxidation state. Ammonia produced in reaction from complex with Zn2+ to give ZnNH242+. The cell has potential of 1.5 V.

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