Which of the following statements is/are correct?

Moderate

A

In the reaction $H_{2} O_{2} + I_{2} ⟶ I^{⊖} +$ X. The missing product (X) is O₂
B

In the reaction $H_{2} O_{2} + I_{2} \to I^{-} +$ X. The missing product (X) is H₂O
C

In the reaction $H_{2} O_{2} + {Sn}^{2 +} ⟶ {Sn}^{4 +} +$ (Y). The missing product (Y) is O₂.
D

In the reaction $H_{2} O_{2} + {Sn}^{+ 2} \to {Sn}^{+ 4}$ + (Y), the missing product(Y) is H₂O

Solution

1) Since I₂ reduced to $I^{⊝}$ , so H₂O₂ must be oxidised to O₂. (Oxidation state of O is zero)
$H_{2} O_{2} + I_{2} ⟶ 2 I^{⊖} + O_{2} + 2 H^{\oplus}$
(4) Sn²⁺ is oxidised to Sn⁴⁺, so H₂O₂ must be reduced to H₂O. (Oxidation state of O is -2)
$2 H^{\oplus} + H_{2} O_{2} + {Sn}^{2 +} ⟶ {Sn}^{4 +} + 2 H_{2} O$

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