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a
The M-M bond energy of C>Si > Ge > Sn
b
The boiling points of elements of 14th group decreases from Si to Pb
c
Carbon is most electronegative among its group
d
The sum of 3rd and 4th ionization energies of Ge is greater that of Si
answer is A.
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Detailed Solution
(a) is correct. As we move down the group the size of the atom increases and hence internuclear distance increase and bond energy decreases from C to Sn C Si Ge SnM-M 348 297 260 240Bond Energy(kJ/mole)b) is correct. As the size of the atom increases attractive forces between the atoms decrease and hence boiling point decreases from Si to Pb. Si Ge Sn PbBoiling point(°C ) 3280 2850 2623 1751c) is correct. Carbon being smallest in size is most electronegative in its family C Si Ge Sn PbElectronegativity order 2.5 1.8 1.8 1.8 1.8(Pauling scale)d) is correct due to improper screeing of s and p-electrons by the inner d electrons in Ge so the sum of 3rd and 4th I. E. of Ge>Si .