Q.

Which of the following statements is/are incorrect?

Moderate

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By Expert Faculty of Sri Chaitanya

Electrical work done in one second is equal to electrical potential multiplied by total charge passed

Charge has to be passed reversibly in order to obtain the maximum work from Galvanic cell

The reversible work done by Galvanic cell is equal to decrease in its Gibbs energy

ΔG=−nEcell

answer is 1.

(Detailed Solution Below)

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Detailed Solution

The standard free energy (∆Go) is related to standard electrode potential (Eo ) and equilibrium constant as ΔG∘=−nFE∘ and ΔG∘=−RTloge⁡Keq Thus,if Ecell ∘ is − ve,then ΔG∘ is + ve,i.e., ΔG∘>0. Hence, Keq would be negative and less than 1, Keq<1.

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