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a
The oxidation number of S in (NH4)2S2O8 is +6
b
The oxidation number of Os in OsO4 is +8
c
The oxidation number of S in H2SO5 is +8
d
The oxidation number of O in KO2 is -1/2
answer is C.
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Detailed Solution
(1) NH4+12S2O82− ∴Oxidation state of S = ±6 (Since S2O82- has one peroxide bond) (2) Oxidation state of Os = +8 (3) Oxidation state of S in H2SO5=+6 (Since it has one peroxide bond) (4) K1+O21-, oxidation state of O =-1/2