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The decreasing order of the numerical value of heat of combustion is:

Cycloalkanes are planar.

Cyclopropane has higher heat of combustion per methylene (-CH2-) group than that of cyclobutane.

with the exception of cyclopropane, cycloalkanes are non-planar.

answer is B.

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Detailed Solution

i. More the number of c atoms, more is the heat of combustion. So, the correct order is (l).ii. Cyclopropane has highest the highest heat of combustion per (CH2) groupiii. Except cyclopropane, cycloalkanes are non-planar.So, the answer is (2).

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