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a
0.1 m Na2SO4
b
0.1 m Al(NO3)3
c
0.1 m MgCl2
d
0.1 m C6H12O6(glucose)
answer is B.
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Detailed Solution
Tb(boiling point)=T0(solvent)+ΔTbΔΤb=m×Kb×im (same)=0.1 molalΔTb∝iGreater the value of i, larger the boiling point of solution. (a) Na2SO4⇌2Na++SO42−,3(d) C6H12O6(non-electrolyte),1(c) MgCl2⇌Mg2++2Cl−,3(b) Al(NO3)3⇌Al3++3NO3−,4