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Q.

Which one is correct for the saturated solution of Ca3(PO4)2 salts if its Ksp is 2.05 × 10-33 ?

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a

Solubility of Ca3(PO4)2 is 1.63×10−6M

b

Ca2+eq. =4.9×10−6M

c

PO43−eq. =3.26×10−6m

d

Ca3(PO4)2eq= Zero

answer is A.

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Detailed Solution

Ca3PO42(s)⇌3Ca2++2PO43−                            3s            2s∴    Ksp=2.05×10−33=108s5∴    s=1.63×10−6M∴    Ca2+=3×1.63×10−6=4.9×10−6MPO43−=2×1.63×10−6=3.26×10−6MCa3(PO4)2eq=0,because all the salt is in ionic state.
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