Which one is correct for the saturated solution of Ca3(PO4)2 salts if its Ksp is 2.05 × 10-33 ?
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a
Solubility of Ca3(PO4)2 is 1.63×10−6M
b
Ca2+eq. =4.9×10−6M
c
PO43−eq. =3.26×10−6m
d
Ca3(PO4)2eq= Zero
answer is A.
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Detailed Solution
Ca3PO42(s)⇌3Ca2++2PO43− 3s 2s∴ Ksp=2.05×10−33=108s5∴ s=1.63×10−6M∴ Ca2+=3×1.63×10−6=4.9×10−6MPO43−=2×1.63×10−6=3.26×10−6MCa3(PO4)2eq=0,because all the salt is in ionic state.