First slide

13th group or boron group

Question

$Which one of the following reacts with {BCl}_{3} to form B_{2} H_{6} ?$

Moderate

A

${LiAlH}_{4}$
B

${NH}_{3}$
C

$Na (Hg)$
D

$K_{2} {Cr}_{2} O_{7}$

Solution

$4 {BCl}_{3} + 3 LiAl H_{4} \overset{}{\to} 2 B_{2} H_{6} + 3 LiCl + 3 {AlCl}_{3}$

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