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a
H22+, He2
b
H2−, He22+
c
H2+, He22−
d
H2−, He22−
answer is A.
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Detailed Solution
(i) H22+⇒B.O=0He2⇒B.0=2−22=0(ii) H2−⇒B.O=2−12=0.5He22+⇒B.O=0(iii) H2+=B.0=1−02=0.5He22−=B⋅O=4−22=1.0(iv) H2−⇒B.O=2−12=0.5He22−⇒B⋅O=4−22=1.0As both H22+ and He2 have zero bond order and hence do not exist