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pH of 1 × 10-8 M HCl is 8

96500 coulomb deposits 1 g equivalent of copper

Conjugate base of H2PO4- is HPO42-

pH + pOH = 14 for all aqueous solution

answer is A.

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Detailed Solution

pH of 10-8 M HCl is slightly less than 7 (HCl is acid)Since it is a very dilute solution, [H+]= (10-8+10-7)M

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