Which of these statement about ${[Co (CN)_{6}]}^{3 -}$ is true

Moderate

A

${[Co (CN)_{6}]}^{3 -}$ has four unpaired electrons and will be in a high-spin configuration.
B

${[Co (CN)_{6}]}^{3 -}$ has no unpaired electrons and will be in a high-spin configuration.
C

${[Co (CN)_{6}]}^{3 -}$ has no unpaired electrons and will be in a low-spin configuration.
D

${[Co (CN)_{6}]}^{3 -}$ has four unpaired electrons and will be in a low-spin configuration.

Solution

${[Co (CN)_{6}]}^{3 -}$ $oxidation no. of Co = + 3$
${Co}^{3 +} = 3 d^{6}$
As $C N^{-}$ is a strong field ligand, so all electrons will be paired up and complex will be low spin complex.

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