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a
Ionic bond
b
Covalent bond
c
Co-ordinate
d
All of three
answer is B.
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Detailed Solution
Electronic configuration of s32−1s2,2s2,2p6,3s2,3p4 In the last orbit it has only 6 electron. So it require 2 electron to complete its octet, therefore it share 2 electron with two hydrogen atom and forms 2 covalent bond with it.