The work done during the expansion of a gas from a volume of 4dm3 to 6dm3 against a constant external pressure of 3atm
is (1Latm=101.32J)
+304J
−304J
−6J
−cosJ
W=−pΔV;W=−3×(6−4)W=−6×101.32(∴1Latm=101.32J)W=−608J