Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The work done during the expansion of a gas from a volume of 4dm3 to 6dm3 against a constant external pressure of 3atmis (1Latm=101.32J)

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

+304J

b

−304J

c

−6J

d

−cos⁡J

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

W=−pΔV;W=−3×(6−4)W=−6×101.32(∴1Latm=101.32J)W=−608J
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
The work done during the expansion of a gas from a volume of 4dm3 to 6dm3 against a constant external pressure of 3atmis (1Latm=101.32J)