First slide
Fundamentals of thermodynamics
Question

The work done in heating one mole of an ideal gas as constant pressure from15C to 25C is

Moderate
Solution

T1=15+273=288KT2=25+273=298K

We know that  :PV1=nRT1  and  PV2=nRT2

Hence  V1=nRT1P  and V2=nRT2P

            V2V1=nRT2PnRT1P i.e., V2V1=nRPT2T1

Or        ΔV=nRPT2T1

But        W=PΔV=P×nRnT2T1

           =nRTnT1

 =nRT2I1 W=1mol×1.987calKmol×(298288)K=19.87cal

So, the correct answer is (d)

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