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The work function for caesium atom is 2 eV,  the threshold wavelength in nm is

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a
654
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754
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854
d
954

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detailed solution

Correct option is A

work function W0=2 eV=2×1.6×10−19J =3.2×10−19J W0=hv0=hcλ0 ∴ λ0=hcW0=6.626×10−34Js×3×108ms−13.2×10−19J =6.5388×10−7 m =653.88nm

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