Work function of metal is 3ev/atom. If light of wavelength 400nm is incident on the metal the maximum kinetic energy of the photoelectrons will be _________ J/atom
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a
1.602×10−21
b
1.602×10−20
c
3.2×10−20
d
3.2×10−19
answer is B.
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Detailed Solution
Energy of incident radiation (ev) =1240400=3.1 evK.E=E-WKEmax=3.1−3ev/atom =0.1 ev/atom =1.602×10−20J/atom (1 ev=1.602 ×10-19 J)