Q.

The work function of a metal is 4.0ev. If the metal is irradiated with radiation of wavelength 300nm,then the maximum K.E  of the photoelectrons would be about

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

6.4×10-19J

b

0.2×10-20J

c

2.0×10-20J

d

2.0×10-19J

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given, λ=300nm =300×10-9m           E=hCλ=6.6×10-34×3×1083×10-7=6.6×10-19J Work function,W=4ev=4×1.6×10-19=6.4×10-19J According to photoelectric effect, E=W+K.E   K.E=6.6×10-19-6.4×10-19=0.2×10-19J=2×10-20J
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon