Q.
The work function of a metal is 4.0ev. If the metal is irradiated with radiation of wavelength 300nm,then the maximum K.E of the photoelectrons would be about
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a
6.4×10-19J
b
0.2×10-20J
c
2.0×10-20J
d
2.0×10-19J
answer is C.
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Detailed Solution
Given, λ=300nm =300×10-9m E=hCλ=6.6×10-34×3×1083×10-7=6.6×10-19J Work function,W=4ev=4×1.6×10-19=6.4×10-19J According to photoelectric effect, E=W+K.E K.E=6.6×10-19-6.4×10-19=0.2×10-19J=2×10-20J
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