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Electromagnetic radiation and spectra

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Question

The work function (ϕ) of some metals is listed below. The number of metals which will show photoelectric effect when light of 300 nm wavelength falls on the metal is 

Moderate
Solution

 The energy associated with incident photon =hcλ

E=6.6×1034×3×108300×109JE in eV=6.6×1034×3×108300×109×1.6×1019=4.16eV

So, number of metals showing photo-electric effects will be 
(4), i.e., Li, Na, K, Mg


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