The work function (ϕ) of some metals is listed below. The number of metals which will show photoelectric effect when light of 300 nm wavelength falls on the metal is
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answer is 4.
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Detailed Solution
The energy associated with incident photon =hcλ⇒E=6.6×10−34×3×108300×10−9JE in eV=6.6×10−34×3×108300×10−9×1.6×10−19=4.16eVSo, number of metals showing photo-electric effects will be (4), i.e., Li, Na, K, Mg