Q.
A 5% (w/v) solution of anhydrous CaCl2 at 0oc developed 15 atm. osmotic pressure . What is the degree of dissociation of CaCl2 .
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a
52.4%
b
5.24%
c
2.43%
d
24.3%
answer is D.
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Detailed Solution
π=CST.i 15=5111×1000100×0.0821×273×i i=15×1115×10×0.0821×273 i=1.48α=i-1n-1 α=1.48-13-1=0.482=0.24=24%
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