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Q.

A 5% (w/v) solution of anhydrous CaCl2 at 0oc developed 15 atm. osmotic pressure . What is the degree of dissociation of CaCl2     .

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a

52.4%

b

5.24%

c

2.43%

d

24.3%

answer is D.

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Detailed Solution

π=CST.i 15=5111×1000100×0.0821×273×i i=15×1115×10×0.0821×273 i=1.48α=i-1n-1 α=1.48-13-1=0.482=0.24=24%
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