Q.

x g of a non-electrolytic compound (molar mass = 200) is dissolved in 1.0 litre of 0.05 M NaCl solution. The osmotic pressure of this solution is found to be 4.92 atm at 27oC. Calculate the value of ‘x’. Assume complete dissociation of NaCl and ideal behaviour of this solution.

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16.52 g

24.032 g

19.959 g

12.35 g

answer is C.

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Detailed Solution

(i) For NaCl: π=iCRT=2×0.05×0.0821×300=2.463 atm(ii) For unknown compound, π=CRT=x200×0.0821×300=0.1231atmTotal osmotic pressure π=π1+π24.92 = 2.463 + 0.1231 xx = 19.959 g

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