Periodicity in atomic properties
Question

# ${\mathrm{X}}_{\left(\mathrm{g}\right)}^{+}\text{\hspace{0.17em}}\to {\mathrm{X}}_{\left(\mathrm{g}\right)}\text{\hspace{0.17em}}\to \text{\hspace{0.17em}}{\mathrm{X}}_{\left(\mathrm{g}\right)}^{-};$$\mathrm{\Delta H}$ for the entire  process -1600 kJ/mole.If IP of ‘X' is 1260 kJ/mole then Electron gain enthalpy of  ‘X’ would be

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Solution

## $\therefore {\mathrm{X}}_{\left(\mathrm{g}\right)}^{+}\text{\hspace{0.17em}}\to \text{\hspace{0.17em}}{\mathrm{X}}_{\left(\mathrm{g}\right)}\text{\hspace{0.17em}}\mathrm{\Delta H}\text{\hspace{0.17em}}=\text{\hspace{0.17em}}-1260\mathrm{kJ}/\mathrm{mole}$${\mathrm{X}}_{\left(\mathrm{g}\right)}^{+}\text{\hspace{0.17em}}\stackrel{-1260}{\to }{\mathrm{X}}_{\left(\mathrm{g}\right)}\text{\hspace{0.17em}}\stackrel{{\mathrm{\Delta H}}_{2}}{\to }\text{\hspace{0.17em}}{\mathrm{X}}_{\left(\mathrm{g}\right)}^{-}$${\mathrm{\Delta H}}_{2}\text{\hspace{0.17em}}=\text{\hspace{0.17em}}-340\mathrm{kJ}/\mathrm{mole}$

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