X grams of Cu(NO3)2 would be needed to take, to get 1.00 g of copper? Find the value of X to the nearest possible integer. Cu = 63.5, N = 14, O = 16.

Mw of CuNO32=63.5+2(14+16×3)=187.5g             CuNO32⟶Cu              1 mol          1 mol           = 187.5 g     = 63.5 g 63.5 g of Cu is obtained from 187.5 g of Cu(NO3)2 1 g of Cu is obtained from =187.563.5=2.9528g≈3