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Q.

‘X’ grams sodium bicarbonate liberated sufficient carbondioxide which can completely oxidize 24 grams of coke, value of ‘X’ is

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a

84 g

b

336 g

c

168 g

d

252 g

answer is B.

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Detailed Solution

CO2g+Cs→2COg1  mole         12 g2  moles         24 g2NaHCO3s→Na2CO3s+H2Og+CO2g2×84g                                                          1  mole    'X'g                                                                      2  molesX = 336 g
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