2 x I08 atoms of carbon are arranged side by side. Calculate the radius of carbon atom, if the length of this arrangement is 2.4 cm.

Let the radius of carbon atom = be r Then,   diameter =2r Number of atoms =2×108  Total length formed =2.4cm ∴ 2r×2×108=2.4 ∴ r=2.44×108=6×10−9Cm =6×10−11m =60×10−12m=60pm