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Question

2 x I0⁸ atoms of carbon are arranged side by side. Calculate the radius of carbon atom, if the length of this arrangement is 2.4 cm.

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Solution

Let the radius of carbon atom = be r
$Then, diameter = 2 r$
$Number of atoms = 2 \times 10^{8} Total length formed = 2 .4 cm ∴ 2 r \times 2 \times 10^{8} = 2 .4 ∴ r = \frac{2 .4}{4 \times 10^{8}} = 6 \times 10^{- 9} Cm = 6 \times 10^{- 11} m = 60 \times 10^{- 12} m = 60 pm$

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