X ml of H2 gas effuses through a hole in a container in 5 seconds. The time taken for the effusion of the same volume of the gas specified below under identical condition is

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10 seconds : He

20 seconds: O2

25 seconds: CO

55 seconds : CO2

answer is B.

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Detailed Solution

r∝1M ∵r= Volume effused time taken =VtVt∝1M∴ for same volumes (V constant)t∝M∴t1t2=M1M2tHc=tH2MHeMH2=542=52s.tO2=t=5322=20stCO=5282=514s;tCO2=5442=522s

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