First slide

Methods to find equivalent weight

Question

6 x 10^-3 mole K₂Cr₂O₇ reacts completely with 9 x 10^-3 mole Xⁿ⁺ to give ${XO}_{3}^{-}$ and ${Cr}^{3 +}$ . The value of n is :

Moderate

A

1
B

2
C

3
D

None of these

Solution

$K_{2} {Cr}_{2} O_{7} + X^{n +} ⟶ X^{5 +} O_{3}^{-} + {Cr}^{3 +}$
6x10^-3 x 6 =(5 -n)x9 x10^-3
n=1

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