Q.
6.02x 1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
0.02 M
b
0.01 M
c
0.001 M
d
0.1 M
answer is B.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Given number of molecules of urea =6.02×1020∴Number of moles =6.02×10206.02×1023=1×10−3molVolume of the solution =100mL=1001000L=0.1LConcentration of urea solution (in mol L-1) =1×10−30.1=1×10−2molL−1 =0.01mol/L or M
Watch 3-min video & get full concept clarity