Q.
6.02x 1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is
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a
0.02 M
b
0.01 M
c
0.001 M
d
0.1 M
answer is B.
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Detailed Solution
Given number of molecules of urea =6.02×1020∴Number of moles =6.02×10206.02×1023=1×10−3molVolume of the solution =100mL=1001000L=0.1LConcentration of urea solution (in mol L-1) =1×10−30.1=1×10−2molL−1 =0.01mol/L or M
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