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Q.

6.02x 1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is

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a

0.02 M

b

0.01 M

c

0.001 M

d

0.1 M

answer is B.

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Detailed Solution

Given number of molecules of urea =6.02×1020∴Number of moles =6.02×10206.02×1023=1×10−3molVolume of the solution =100mL=1001000L=0.1LConcentration of urea solution (in mol L-1)                                 =1×10−30.1=1×10−2molL−1    =0.01mol/L or M
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6.02x 1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is