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$_{35} X^{88}$ is an unstable isotope, decays in two successive steps to produce stable(s) isotope $_{36} Y^{87}$ ,as shown as ${}_{35}X^{88} \overset{I}{\to} Z {\overset{II}{\to}}_{36} Y^{87}$
The correct statement(s) is/are

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I involve a β-emission

II involve a neutron emission

If I involve β-emission, y and Z must be isotopes

X and Z will always be isotones

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detailed solution

Correct option is A

Z = X 3688X and Z are isobars

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35X88 is an unstable isotope, decays in two successive steps to produce stable(s) isotope 36Y87 ,as shown as X 88 35 →IZ→II36Y87The correct statement(s) is/are

Unlock the full solution & master the concept.

Ready to Test Your Skills?

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$_{35} X^{88}$ is an unstable isotope, decays in two successive steps to produce stable(s) isotope $_{36} Y^{87}$ ,as shown as ${}_{35}X^{88} \overset{I}{\to} Z {\overset{II}{\to}}_{36} Y^{87}$
The correct statement(s) is/are