Q.

X and Y respectively in the above conversion are

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a

Kolbe's  electrolysis  ;   CH3CH2CH2Cl/FeCl3

b

NaOH+CaO/Δ ;   CH3CH2CH2Cl/anhydrousAlCl3

c

Zn/Δ ; CH3CH2 CH2Cl/anhydrousAlCl3

d

NaOH+CaO/Δ ;  CH3CH2CH2Cl/FeCl3

answer is B.

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Detailed Solution

1st step is decarboxylation. It is carried out by heating C6H5COONa with soda lime (NaOH +CaO)C6H5COONa+NaOH→ΔCaOC6H6+Na2CO3A→BCH3CH2CH2Cl+AlCl3→CH3CH2C+H2+AlCl4−CH3−CH2−C+H2⇌shift1,  2  H-CH3−C+H−CH3H++AlCl4−→AlCl3+HClIn presence of FeCl3, rearrangement of carbocation cannot occur. FeCl3 is a weaker Lewis acid as compared to anhydrous AlCl3.in such case,
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X and Y respectively in the above conversion are