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Q.

Xe(g)+PtF6(g)⟶APtF6 25∘C⟶BPtF6 60∘C⟶CThe products are:(I) Xe⊕PtF6⊖        (II) [XeF]⊕PtF11⊖      (III) [XeF]⊕Pt3F16⊖     (IV) XeF2⊕Pt2F11⊖  (V) XeF3⊕Pt3F16⊖  (VI) [XeF]⊕PtF6⊖

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a

I, VI, II

b

I, Il, III

c

VI, II, III

d

I, IV V

answer is A.

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Xe(g)+PtF6(g)⟶APtF6 25∘C⟶BPtF6 60∘C⟶CThe products are:(I) Xe⊕PtF6⊖        (II) [XeF]⊕PtF11⊖      (III) [XeF]⊕Pt3F16⊖     (IV) XeF2⊕Pt2F11⊖  (V) XeF3⊕Pt3F16⊖  (VI) [XeF]⊕PtF6⊖