Q.
XeF6 cannot be stored in glass vessel because silica (SiO2)
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a
XeF5⊕
b
XeO3
c
XeO2F2
d
XeOF4
answer is B.
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Detailed Solution
(i) 2XeF6+SiO2⟶2XeOF4+SiF4 (ii) 2XeOF4+SiO2⟶2XeO2F2+SiF4 (iii) 2XeOF4+2SiO2⟶2XeO3+2SiF4
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