XeF6 cannot be stored in glass vessel because silica (SiO2)

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XeF5⊕

XeO3

XeO2F2

XeOF4

answer is B.

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Detailed Solution

(i) 2XeF6+SiO2⟶2XeOF4+SiF4 (ii) 2XeOF4+SiO2⟶2XeO2F2+SiF4 (iii) 2XeOF4+2SiO2⟶2XeO3+2SiF4

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